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14x+8x-24=2x^2+8x
We move all terms to the left:
14x+8x-24-(2x^2+8x)=0
We add all the numbers together, and all the variables
22x-(2x^2+8x)-24=0
We get rid of parentheses
-2x^2+22x-8x-24=0
We add all the numbers together, and all the variables
-2x^2+14x-24=0
a = -2; b = 14; c = -24;
Δ = b2-4ac
Δ = 142-4·(-2)·(-24)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2}{2*-2}=\frac{-16}{-4} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2}{2*-2}=\frac{-12}{-4} =+3 $
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